`1.5x + 0.8y = 2.3, 0.3x - 0.2y = 0.1` Solve the system by the method of substitution.

First multiply everything by 10 to get whole numbers.

Solve equation [2] for the variable  x 
 

`3x = 2y + 1`

`x = 2y/3 + 1/3`

Plug this in for variable  x  in equation [1]

`15(2y/3+1/3) + 8y = 23`
`18y = 18`

Solve equation [1] for the variable  y 

`18y = 18`

`y = 1`  

By now we know this much :

`x = 2y/3+1/3`
`y = 1`

Use the  y  value to solve for  x 

`x = (2/3)(1)+1/3 = 1`

The solution is `(1,1)`