Let the year be represented by abcd where a is in the thousands place, b is in the hundreds place, c in the tens place and d in the units place.
We are given that bxd=72 (hundreds digit times unit digit is 72). And we are given that the hundreds digit is 1 more than the units digit so b=d+1. Then b=9 and d=8. (You can get this by guess and check: 5x4=20,6x5=30,...,8x7=56,9x8=72) or if you have algebra:
d(d+1)=72 ==> d^2+d-72=0 ==> (d+9)(d-8)=0 ==> d=8 (since d>0)
Also c=5 since the number of sides of a pentagon is 5.
The sum of the digits is one less than 2 dozen or 24-1=23.
So a+b+c+d=a+9+5+8=23 ==> a=1
The year was 1958
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