`(4x^2+2x-1)/[x^2(x+1)]=A/x+B/x^2+C/(x+1)`
Multiply through by the LCD `x^2(x+1).`
`4x^2+2x-1=Ax(x+1)+B(x+1)+Cx^2`
`4x^2+2x-1=Ax^2+Ax+Bx+B+Cx^2`
`4x^2+2x-1=(A+C)x^2+(A+B)x+B`
Equate the coefficients of like terms. Then solve for A, B, and C.
`B=-1`
`2=A+B`
`2=A-1`
`A=3`
`4=A+C`
`4=3+C`
`C=1`
`A=3, B=-1, C=1`
`(4x^2+2x-1)/[x^2(x+1)]=3/x-1/x^2+1/(x+1)`
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