if you were to multiply 2973 and 2095 how would you set it out as a colum addition method? important parts in this question 2973 2095 colum...

Write the numbers in a column as mentioned below

                       2   9   7   3

                  X   2   0   9   5

Lets now find out the numbers which we need to add in column by multiplication.

1. Multiply 2973 by the unit's digit of second number i.e. 5, we get 14865. This is the first number of our column.

2. Multiply 2973 by 90,9 is in tens place. we get 267570. This is the second number of the column

3. Next digit is 0. So the result is also 0 for the multiplication by it.

4. Multiply 2973 by 2000, 2 is in thousands place, we get 5946000. This is the third number of the column

5. Now list down all these numbers as a column and add them.

                          1   4   8   6   5

                     2   6   7   5   7   0

             + 5   9   4   6   0   0   0 

                6   2   2   8   4   3   5

This is the required answer.