Let N be the number you want to get the square root. Assume E1 as the initial estimate for `sqrtN` .
So the next estimate E2 will be;
`E2 = (N/(E1)+E1)/2`
Similarly E3 will be;
`E3 = (N/(E2)+E2)/2`
For 110.6;
We know that `sqrt100 = 10` and `sqrt121 = 11`
So let us estimate E1 = 10 for ease of calculation.
`E2 = (110.6/10+10)/2 = 10.53`
If you need further accuracy you can estimate E3 as well.
`E3 = (110.6/10.53+10.53)/2 = 10.517`
For 10080;
We know that `sqrt10000 = 100`
So let us say E1 = 100.
`E2 = (10080/100+100)/2 = 100.4`
Similarly;
`E3 = (10080/100.4+100.4)/2 = 100.399`
So the answers are;
`sqrt110.6 = 10.517`
`sqrt10080 = 100.399`
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