Hello!
No, 2003 isn't divisible by 3. Strictly speaking, there is no such integer that
although such rational number exists.
To prove this, express 2003 as 3*667 + 2, which means the remainder of division of 2003 by 3 is 2. If 2003 would divisible by 3, then
2 = 2003 - 3*667
would be also divisible by 3, which is false.
Also there is a simple divisibility rule: a decimal integer N is divisible by 3 if and only if the sum of digits of N is divisible by 3.
The cause of this rule is that 10 gives the remainder 1 after division by 3. Therefore 100, 1000 and all other powers of 10 give the remainder 1 after division by 3.
In our case 2003 becomes 2+0+0+3=5, which isn't divisible by 3.
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