`(1/2)x + (3/4)y = 10, (3/4)x - y = 4` Solve the system by the method of substitution.

Express `y` from the second equation: `y=(3/4)x-4,` and substitute it into the first equation:

`(1/2)x+(3/4)*((3/4)x-4)=10,` or

`(1/2)x+(9/16)x-3=10,` or

`(17/16)x=13.`

So `x=(16*13)/17=12+4/17` and `y=(3/4)*(12 +4/17)-4=9+3/17-4=5+3/17.`

The answer: x = 12 and 4/17, y = 5 and 3/17.