`int_1^4 f(x) dx= 7`
Find `int_1^4 (2f(x) + 5)dx` .
To solve, express this as sum of two integrals.
`int_1^4 (2f(x) + 5)dx`
`=int_1^4 2f(x) dx + int_1^4 5dx`
Then, factor out the 2 in the first integral.
`= 2int_1^4 f(x) dx + int_1^4 5dx`
Plug-in the given `int_1^4 f(x) dx= 7` .
`=2(7) + int_1^4 5 dx`
`= 14 + int_1^4 5 dx`
For the second integral, apply the formula int c dx = cx.
`= 14 + 5x|_1^4`
To evaluate the definite integral, apply the formula `int_a^b f(x) dx = F(b) - F(a)` .
`= 14 + (5*4 - 5*1)`
`=14 + 15`
`= 29`
Therefore, `int_1^4 (2f(x) + 5)dx = 29` .
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