`int (3t + 2)^2.4 dt` Evaluate the indefinite integral.

You need to use the following substitution  `3t + 2=u` , such that:

`3t + 2=u=>3dt= du => dt = (du)/3`

`int (3t + 2)^(2.4) dt = (1/3)*int u^2.4 dt`

`(1/3)*int u^2.4 dt = (1/3)*(u^(2.4+1))/(2.4+1) + c`

Replacing back  `3t + 2` for u yields:

`int (3t + 2)^(2.4) dt =(1/3)*((3t+2)^(3.4))/(3.4) + c`

Hence, evaluating the indefinite integral, yields `int (3t + 2)^(2.4) dt =(1/3)*((3t+2)^(3.4))/(3.4) + c`