Hello!
To factor a polynomial `p(x),` it is sufficient to find its roots, `p(x)=0.`
Here `p(x)=x^2-x-6` and the equation is `x^2-x-6=0.`
The roots may be guessed, the integer ones must be factors (positive or negative) of `-6.` Also this equation may be solved as a quadratic one by the formula.
Regardless of a method, the roots are `x=3` and `x=-2` (you may check). The factored form is therefore
`x^2-x-6=(x-3)(x+2)`
(check also by opening the parentheses). `x+2` is the same as `x-(-2).`
The coordinates of the roots are (3, 0) and (-2, 0) (`y=0` because they are roots, or zeros).
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