Hello!
Denote the impulse of the ball right before a foot strikes it as It is a vector directed downwards with the magnitude of
We'll find the speed
later.
The resulting impulse (a vector also) has a magnitude
where
is given. Its direction is also given.
Therefore the impulse delivered by a foot may be found from the equation
i.e.
First find the speed The height of a free fall is given by
where
and the speed is
at
so
Now decompose the vectors and
by horizontal and vertical parts.
Therefore The magnitude of this vector is approx.
and the angle above horizontal is
°. This is the answer.
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