`int s 2^s ds` Evaluate the integral

You need to use the integration by parts such that:

`int fdg = fg - int gdf`

`f = s => df = ds`

`dg = 2^s=> g = (2^s)/(ln 2)`

`int s*2^s ds = s* (2^s)/(ln 2) - int (2^s)/(ln 2) ds`

`int s*2^s ds = s* (2^s)/(ln 2) - (2^s)/(ln^2 2)) + c`

Hence, evaluating the integral, using  integration by parts, yields `int s*2^s ds = (2^s)/(ln 2)(s - 1/(ln 2)) + c`