`a_n = (-1)^n(n/(n+1))` Write the first five terms of the sequence. (assume that n begins with 1.)

`a_n=(-1)^n(n/(n+1))`

`a_1=(-1)^1(1/(1+1))=(-1)(1/2)=-1/2`

Plug in n=2, to get the 2nd term

`a_2=(-1)^2(2/(2+1))=(-1)(-1)(2/3)=2/3`

Plug in n=3, to get the 3rd term

`a_3=(-1)^3(3/(3+1))=(-1)(-1)(-1)(3/4)=-3/4`

Plug in n=4, to get the 4th term

`a_4=(-1)^4(4/(4+1))=(-1)(-1)(-1)(-1)(4/5)=4/5`

Plug in n=5, to get the 5th term

`a_5=(-1)^5(5/(5+1))=(-1)(-1)(-1)(-1)(-1)(5/(5+1))=-5/6`

So, the first five terms of the sequence are `-1/2,2/3,-3/4,4/5,-5/6`