The augmented matrix is `[[1,2,1,8],[3,7,6,26]]`
On applying `R_2 -gt R_2 - 3R_1` we get
`[[1,2,1,8],[0,1,3,2]]`
On applying `R_1 -gt R_1 - 2R_2 ` we get
`[[1,0,-5,4],[0,1,3,2]]`
The corresponding system is `x -5z = 4`
`y +3z = 2`
Let `k ` is any real number and` z = k` , now substitute `z ` value in the above equations to find `x` and `y` values.
`x - 5z = 4`
`x = 4 + 5z = 4 + 5k`
`y +3z = 2`
`y = 2- 3z = 2 - 3k`
`therefore` the solution set is `{4 + 5k, 2 - 3k, k}`
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