Write an expression for the apparent nth term of the sequence. (assume that n begins with 1)

If you look at this sequence, you notice that the pattern is pretty much made up of fractions with different numbers in the denominator and 1's in the numerator. So let's look at the denominators. Right here, we see 1, 2, 6, 24, and 120. Does that pattern remind you of anything? It is a sequence made up of factorials, or !. A factorial of x would be all the positive integers multiplied together all the way up to and including x. Therefore, 1!=1, 2!=2*1=2, 3!=3*2*1=6, and so on. Therefore, the sequence is (1/n!), where n begins at 1 and is the nth term of the sequence.