`int sin(ln(x))/x dx` Evaluate the indefinite integral.

You need to use the following substitution  `ln x = t` , such that:

`ln x= t => (dx)/(x) = dt`

`int (sin(ln x))/(x) dx = int sin t dt`

`int sin t dt= - cos t + c`

Replacing back  `ln x` for t yields:

`int (sin(ln x))/(x) dx = - cos (ln x) + c`

Hence, evaluating the indefinite integral, yields` int (sin(ln x))/(x) dx = - cos (ln x) + c.`